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Algebra Level 1

Find the largest of five consecutive numbers whose sum is 500.


The answer is 102.

Anish Harsha by Anish Harsha , 20, India

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3 solutions

x+(x+1)(x+2)(x+3)(x+4)=500 => 5x+10=500 =>x=98 Therefore, largest number, x+4 = 102

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Better solution...

Heder Oliveira Dias - 6 years, 7 months ago
Ashish Menon
May 31, 2016

Let the numbers be x , x + 1 , x + 2 , x + 3 , x + 4 x, x+1, x+2, x+3, x+4 .
So, x + x + 1 + x + 2 + x + 3 + x + 4 = 500 5 x + 10 = 500 5 x = 490 x = 98 x + x + 1 + x + 2 + x + 3 + x + 4 = 500\\ 5x + 10 = 500\\ 5x = 490\\ x = \color{#69047E}{\boxed{98}}

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Azadali Jivani
Aug 1, 2015

x+(x+1)+(x+2)+(x+3)+(x+4))=500
5 x + 10 = 500
x = 98
x + 4 = 102 (Ans.)


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