Replace each star with an integer, such that the sum of any three consecutive numbers is 20.
Find the smallest possible value of the .
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7 A B C D E F 9 Since 7 + A + B = A + B + C , by subtracting A + B , we get 7 = C .
Since E + F + 9 = D + E + F , by subtracting E + F , we get 9 = D .
Since C + D + E = 2 0 , we get E = 2 0 − C − D = 2 0 − 7 − 9 = 4 .
Therefore the answer is 4 .