Bijective Function

For two sets X = { x x 19 } , Y = { y y 361 } , X=\{x\mid x\geq 19\}, Y=\{y\mid y\geq 361\}, function f : X Y f: X \to Y is defined as f ( x ) = x 2 2 x + a . f(x)=x^2-2x+a. If f f is a one-to-one, bijective function, what is the value of the constant a ? a?

38 40 36 42

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1 solution

Maheep Chowdary
Apr 20, 2014

it is given that it is a bijective function then the image of 19 is 361 then f(19)=x2-2x+a since the image of 19 is 361 we can take x=19 therefore 361=(19)whole square-2x+a 361=361-19(2)+a 0=-38+a a=38

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