Binary insertion sort

The standard Θ ( n 2 ) \Theta(n^{2}) implementation of insertion sort on an array uses linear search to identify the position to insert an element into an already sorted sub-array. Now suppose we use a binary search to identify the position to insert an element, what will be the worst-case running time of the new algorithm?

Θ ( n log n ) \Theta(n\log n) Θ ( n ( log n ) 2 ) \Theta(n(\log n)^{2}) remains Θ ( n 2 ) \Theta(n^{2}) Θ ( n ) \Theta(n)

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