Binary Powers of 10 10

Algebra Level 2

A hacker can hack 1 1 bit/s. How much time does he need to hack 64 64 MiB of data in seconds?

Notes:

  • 8 8 bits = 1 =1 byte
  • 1 1 MiB(Mebibyte) = 2 20 =2^{20} bytes


The answer is 536870912.

Lâm Lê by Lâm Lê , 13, Australia

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1 solution

Time needed is 64 × 8 × 2 20 = 536870912 64\times 8\times 2^{20}=\boxed {536870912} sec.

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