Binary X-Grid

Probability Level 2

How many different ways are there to fill a 4 × 4 4 \times 4 grid with 1 and 0, such that the diagonals have no 0?

1024 128 256 512

Ossama Ismail by Ossama Ismail , 63, Egypt

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1 solution

David Vreken
Feb 19, 2019

Since the diagonals have no 0 0 , they must all be 1 1 :

This leaves 8 8 squares that can be either 0 0 or 1 1 , for a total of 2 8 = 256 2^8 = \boxed{256} different ways.

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