Binomial!

S = ( 404 4 ) ( 303 4 ) ( 4 1 ) + ( 202 4 ) ( 4 2 ) ( 101 4 ) ( 4 3 ) = ( 101 ) k S= \dbinom{404}{4}-\dbinom{303}{4}\dbinom{4}{1}+\dbinom{202}{4}\dbinom{4}{2}-\dbinom{101}{4}\dbinom{4}{3}= (101)^k

Find k k .

1 2 6 4

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1 solution

Given expression is the coefficient of x 4 x^4 in the expansion of :

( 1 ( 1 + x ) 101 ) 4 (1-(1+x)^{101})^4

= ( ( 101 1 ) x + ( 101 2 ) x 2 + ) 4 =\left(\dbinom{101}{1}x+\dbinom{101}{2}x^2 + \cdots \right)^4

which is ( 101 1 ) 4 \dbinom{101}{1}^4

= ( 101 ) 4 =(101)^4

Hence, k = 4 \boxed{k=4}

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