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1 solution
C(10,7)+C(9,6)+...+C(3,0)=C(10,3)+C(9,3)+.....+C(3,3)= becouse C(n,k)=C(n,n-k). Is the sum of the first 8 numbers in 4th diagonal of Tartaglia's triangle Then =C(8+3,4)=C(11,4)=330