Binomial Trouble!

Consider the alternating sum of binomial coefficients below: ( n 1 ) ( n 3 ) + ( n 5 ) ( n 7 ) + ± ( n m ) = 0 , \binom n1 - \binom n3 + \binom n5 - \binom n7 + \cdots \pm \binom nm = 0, where m m denotes the largest odd number less than or equal to n n .

Which of the following options must be true for any positive integer k k ? Justify your answer.


Notation: ( M N ) = M ! N ! ( M N ) ! \dbinom MN = \dfrac {M!}{N! (M-N)!} denotes the binomial coefficient .

n = 4 k n=4k n = k n=k n = 2 k 1 n=2k-1 n = 2 k n=2k

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