Binomial trouble

Here, $T_{r+1}= ^{1024}C_{r}5^{\frac{1024-r}{2}}7^{\frac{r}{8}}$ Clearly, integral terms would be an intersection of the values from the set of $5$ and $7$ ,i.e. $\dfrac{1024}{8} = 128$ .
But, initial term is skipped, so answer= $128+1 =129$