There are two sets of birds on different branches: say group A and group B.
One of the group A says if one of you ( group B ) will come to us, then we will be twice number of you, then one of the group B says: no, no, if one of you ( group A ) will come to us , then we will be equal to you.
Find the number of birds in A and number of birds in B
type your answer like this:
xy ( without any space, without any comma )
( x represents number of A birds ...y represents number of B birds )
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This is exactly the same as this question . Anyway...
Transform the sentences into equations:
x + 1 = 2 ( y − 1 ) ⟹ Eq.(1)
x − 1 = y + 1
x = y + 2 ⟹ Eq.(2)
Substitute Eq.(2) into Eq.(1):
y + 2 + 1 = 2 ( y − 1 ) y + 3 = 2 y − 2 y = 5 x = 5 + 2 = 7
The answer is entered in the form of x y , which is 7 5
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A has twice the number of birds as B so A has 3 2 the total number of birds while B has 3 1 . If A and B have an equal number, each has half. This means a difference of 6 1 in each nest. Observe also that one bird from A to B and one bird from B to A means a difference of two birds in each nest. So onesixth is equal to two birds which means there are a dozen birds in all. It is now easy to see that A has seven while B has five.