There are male and female doves on a fence. When 5 male doves leave, there remain 2 female doves for every male dove. Then 25 female doves leave, there are now 3 male doves for every female dove. Find the original number of male doves.
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f m − 5 = 2 1 ⟹ 1
f − 2 5 m − 5 = 1 3 ⟹ 2
From 1 , we get f = 2 m − 1 0 . Substitute f in 2 .
2 m − 1 0 − 2 5 m − 5 = 3
m − 5 = 6 m − 3 0 − 7 5
1 0 0 = 5 m
2 0 = m
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Let the original numbers of male and female doves on the fence be m and f respectively. Then we have:
f 3 ( f − 2 5 ) 3 ( 2 m − 1 0 − 2 5 ) 6 m − 1 0 5 5 m ⟹ m = 2 ( m − 5 ) = m − 5 = m − 5 = m − 5 = 1 0 0 = 2 0 Note that f = 2 ( m − 5 )