Black Hole Identified #2
Even massless photon can't escape a black hole, let alone particles with mass!
But Hawking Radiation is the one and only something which is assumed to escape the black hole, somehow . [Notice that, this "somehow" is a clue]
Now tell, Is everything unable to escape from the surface of the black hole?
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1 solution
Hawking Radiation appears from the Event Horizon of the black hole.
In 1974, Hawking shocked the physics world by showing that black holes should in fact thermally create and emit sub-atomic particles, known today as Hawking radiation , until they exhaust their energy and evaporate completely. According to this theory, black holes are not completely black, and neither do they last forever. Hawking showed how the strong gravitational field around a black hole can affect the production of matching pairs of particles and anti-particles, as is happening all the time in apparently empty space according to quantum theory . If the particles are created just outside the event horizon of a black hole , then it is possible that the positive member of the pair (say, an electron ) may escape - observed as thermal radiation emitting from the black hole - while the negative particle (say, a positron, with its negative energy and negative mass) may fall back into the black hole , and in this way the black hole would gradually lose mass. This was perhaps one of the first ever examples of a theory which synthesized, at least to some extent, quantum mechanics and general relativity .
So, true to say, hawking radiation isn't emitted from the core of a black hole. It comes from the event horizon of the black hole.
Nothing is able to escape from the black hole surface, but Hawking Radiation is able to escape from Event Horizon, not from the surface.