Black Holes Part 2

$\Delta T = \frac{hc^{3}}{16\pi^{2}Gk_{B}} \left ( \frac{1}{M} - \frac{1}{M_{0}} \right ) \approx 1.227 \times 10^{23} \times \left ( \frac{1}{M} - \frac{1}{M_{0}} \right )$

where $M$ stands for the final mass of the BH and $M_{0}$ stands for the initial mass of the BH.

Temperature ${ T }_{ h }$ of black hole is given by:

${ T }_{ h }=\frac { \hslash { c }^{ 3 } }{ 8\pi GM{ k }_{ b } }$

Where:

$M$ is mass of black hole.

$c$ is speed of light.

${ k }_{ b }$ is the Boltzmann constant.

$\hslash$ is Planck's constant divided by $2\pi$

$G$ is the universal gravitational constant.

In the question, $M_{\odot}$ represents mass of our sun.

Just substitute and subtract to arrive at answer.

Source: Wikipedia