Blank Space Part 5

Logic Level 3

3 4 5 \large 3 \, \square \, 4 \, \square \, 5

There are 4 2 = 16 4^2 = 16 ways in which we can fill the squares with + , , × , ÷ +, -, \times, \div .

Of all these 16 ways, there are two numbers for which their sum is 0. What is the product of these two numbers?

Note :
You are not allowed to use parenthesis.
Obey the order of operations.


The answer is -289.

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2 solutions

Nihar Mahajan
Jul 26, 2015

3 4 × 5 = 17 3 × 4 + 5 = 17 p r o d u c t = 17 × ( 17 ) = 289 3-4\times 5 = -17 \\ 3\times 4 + 5=17 \\ \Rightarrow \ product \ = \ 17 \times (-17) = \boxed{-289}

very poorly written problem .

Joshua Coddington - 5 years, 9 months ago

It would be interesting to see the program to solve in case of bigger digits or more operations...

Leonblum Iznotded - 2 years, 10 months ago
Gabriel Hercúles
Aug 17, 2015

As the sum of the numbers is 0, they should be equal in magnitude but must have opposite signs.
3- 4 x5= -17
3x4 +5=17
17+(-17)=0
So, those are the numbers.
(-17)x(17)= - 289



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