Block,spring and an inclined plane.
In figure, a block weighing
, which can slide
without friction on an incline at angle
, is connected to
the top of the incline by a massless spring of un stretched length
and spring constant
. How far from the top of
the incline is the block's equilibrium point?
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The answer is 0.525.
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Component of force parallel to the incline=14sin40. In order to reach equilibrium net force on block = 0 Let the block reach equilibrium when spring get displaced by x from its mean position. So 120k=14sin40. To find the distance from the top of the incline to the block's equilibrium point simply add x to 0.45