An oil have a density of floats on water. A rectangular block of wood high and with a density floats partly in the oil and partly in the water. The oil completely covers the block. How far below the interface between the two liquids is the bottom of the block? (in meters)
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Assume the cross-sectional area of the block to be A m² and x met. to be the block depth in water. Then, Weight of wooden block = Weight of displaced water + Weight of displaced oil or 0.04(A)(960) = x(A)(1000) + (.04-x)(A)(930), which readily yields, x = 0.0171429 met.