Block, water and a bit of oil?

An oil have a density of 930 kg/m 3 930\text{ kg/m}^3 floats on water. A rectangular block of wood 4 cm 4\text{ cm} high and with a density 960 kg/m 3 960\text{ kg/m}^3 floats partly in the oil and partly in the water. The oil completely covers the block. How far below the interface between the two liquids is the bottom of the block? (in meters)


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The answer is 0.017.

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2 solutions

Ajit Athle
Sep 12, 2016

Assume the cross-sectional area of the block to be A m² and x met. to be the block depth in water. Then, Weight of wooden block = Weight of displaced water + Weight of displaced oil or 0.04(A)(960) = x(A)(1000) + (.04-x)(A)(930), which readily yields, x = 0.0171429 met.

Asad Jawaid
Sep 11, 2016

Its sideways!!!! :P

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