Blowing Bubbles

John is blowing bubbles from point P P which is 1 1 m above the ground. Then a bubble travels along the path P Q R , P \to Q \to R, where it lands and bursts. The distance of the path P Q P\to Q and that of Q R Q\to R are the same, which is 1.5 1.5 m. The time taken flying each of those two paths is also the same, which is 2 2 seconds. What are the magnitude of the average speed and the magnitude of the average velocity, respectively, of the bubble traveling from P P to R ? R?

0.25 m/s, 0.75 m/s 0.25 m/s, 0.25 m/s 0.50 m/s, 0.50 m/s 0.75 m/s, 0.25 m/s

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3 solutions

average speed = total distance/ total time required = (1.5+1.5)/(2+2)=0.75 m/sec

Velocity (vector quantity) = total displacement/total time required = 1/(2+2)=0.25 m/sec

Jay Shah
Mar 13, 2014

speed=distance/time=1.5+1.5/2+2=3/4=0.75

velocity=displacement/time=1/2+2=1/4=0.25

Nidhay Prakashkar
Mar 13, 2014

Av speed = total distance travelled / total time taken= 1.5+1.5/2+2= 3/4=0.75m/s. Av velocity=total displacement / total time taken= 1/2+2=1/4=0.25m/s...

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