Mind-Blowing Bowling!

Let $x$ be the number of points Mohhawk had from all of his games except the last one. Let $n$ be the number of games he has played except the last one.

Before he plays his last game, his average is $\frac{x}{n}=205$ .

After his plays his last game, his average is $\frac{x+241}{n+1}=209$ .

Use the two equations to solve for the two unknowns: $x=1640$ and $n=8$ . So he has $1640$ total points in $8$ games.

We want the average to be $211$ after $9$ games, meaning $\frac{1640+y}{9}=211$ , in which $y$ is the number of points of the ninth game.

$\boxed{y=259}$

Let x be the number of times Mohhawk has already played before his last game. x+1 means his last game. To find the average score, one must divide the total scores by the number of games played.

205x= total scores before the last game 241= last game's score 205x+241= total score after the last game 209x= IS ALSO THE TOTAL SCORE AFTER THE LAST GAME

Thus,

205x+241= 209x This would give us 8 as the x. Meaning, Mohhawk has played 9 games in all. The question would be Mohhwak's score (supposedly) if he hasn't gotten 241, to get an average score of 211.

So 211x= supposed total score 205x= total scores before the last game.

We know now that x=8. 205(8) is 1640. 211(8)= 1899

1899-1640 gives us 259.