Bob's chocolate bar

Geometry Level 3

Bob just purchased a chocolate bar made out of 15 identical square pieces with an area of 4 c m 2 \SI{4}{\centi\meter\squared} each. He has already eaten 2 pieces and his bar now looks like this:

Bob then proceeds to cut his chocolate bar into 3 pieces, not necessarily along the grid lines. He then rearranges these 3 pieces into one big square with an area of 52 c m 2 . \SI{52}{\centi\meter\squared}.

What is the area of the biggest piece of the three, in c m 2 ? \si{\centi\meter\squared}?


The answer is 28.

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1 solution

Simon Veilleux
Apr 20, 2018

The only way to cut your chocolate bar into trhee pieces that will form a square is like this : Since every square has an area of 4cm², we know that its side lenght is 2cm. The larger piece is formed of 2 triangles and a square. The two triangles are identical and have a base of 6cm and a height of 4cm. The total area is the sum of the areas of the two triangles plus the area of the square.

A = 2 × 6 × 4 2 + 4 = 28 A = 2 \times \frac {6 \times 4}{2} + 4 = \boxed{28}

Two things: 1. Typo of chocolate in the question 2. I think it should be given in the question to confirm that the cuts are straight and don't have to go along the lines between the pieces

Stephen Mellor - 3 years, 1 month ago

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