BODMAS rule!

Algebra Level 1

( 2 + 3 × 6 8 9 ÷ 2 + ( 3 + ( 9 ) ) ÷ 11 × 11 ) × 10 ÷ 5 = ? (2 + 3 \times 6 - 8 - 9 \div 2 + (3 + (-9)) \div 11 \times 11) \times 10 \div 5 = \, ?

Hint : Use BODMAS rule .


The answer is 3.

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1 solution

Hung Woei Neoh
Jul 9, 2016

( 2 + 3 × 6 8 9 ÷ 2 + ( 3 + ( 9 ) ) ÷ 11 × 11 ) × 10 ÷ 5 = ( 2 + 3 × 6 8 9 ÷ 2 + ( 3 9 ) ÷ 11 × 11 ) × 10 ÷ 5 = ( 2 + 3 × 6 8 9 ÷ 2 + ( 6 ) ÷ 11 × 11 ) × 10 ÷ 5 = ( 2 + 18 8 4.5 6 ) × 10 ÷ 5 = 1.5 × 10 ÷ 5 = 3 (2+3 \times 6 - 8 - 9 \div 2 +(3 \color{#D61F06}{+(-9)})\div11 \times 11) \times 10 \div 5\\ =(2+3 \times 6 - 8 - 9 \div 2 + \color{#D61F06}{(3-9)}\div11 \times 11) \times 10 \div 5\\ =(2+\color{#D61F06}{3 \times 6} - 8 - \color{#D61F06}{9 \div 2} + \color{#D61F06}{(-6)\div11 \times 11}) \times 10 \div 5\\ =\color{#D61F06}{(2+18-8-4.5-6)} \times 10 \div 5\\ =\color{#D61F06}{1.5 \times 10 \div 5}\\ =\boxed{3}

Why dont you become an artist, you use your colours properly :P? Nice solution!

Ashish Menon - 4 years, 11 months ago

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Using colors here would be the easiest way to highlight what should be done first without lengthy explanations

Hung Woei Neoh - 4 years, 11 months ago

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Agreed! (+1)

Ashish Menon - 4 years, 11 months ago

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