BODMAS

Algebra Level 1

( 4 7 ) + 2 2 ÷ 3 × 6 = ? \large (4-7)+2^{ 2 }\div 3\times 6 = \ ?

5 4 1/18 2

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2 solutions

Adam Blakey
Sep 25, 2015

By BODMAS (or BIDMAS , or PEDMAS ), we know the order in which we should execute each operation:

  1. Brackets
  2. Order (powers)
  3. Division
  4. Multiplication
  5. Addition
  6. Subtraction

We can add brackets (don't be scared by the different types of brackets — (), [], {} — they can be used interchangeably in this case) to our original equation to make it easier to see when each operation should be applied: x = [ ( 4 7 ) + ( [ 2 2 ] ÷ 3 × 6 ) ] x = [(4-7)+({[2^2] \div 3} \times 6)] .

So, we should: first equate the brackets at the front (4-7), to give us -3; x = [ ( 3 ) + ( [ 2 2 ] ÷ 3 × 6 ) ] x = [(-3)+({[2^2] \div 3} \times 6)] we then raise 2 to the power of 2, to give us 4; x = [ ( 3 ) + ( [ 4 ] ÷ 3 × 6 ) ] x = [(-3)+({[4] \div 3} \times 6)] then divide that by 3, to give us 4/3; x = [ ( 3 ) + ( 4 3 × 6 ) ] x = [(-3)+({\frac{4}{3}} \times 6)] then times that by 6 to give us 8; x = [ ( 3 ) + ( 8 ) ] x = [(-3)+(8)] then add -3 and 8 to give us: x = 5 x = 5 .

Ervin Cunanan
Oct 4, 2015

Please Excuse My Dear Aunt Sally (PEMDAS)

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