A great bombard launches a projectile in a high arc, with an initial velocity of 49.0 m/s vertical component upwards and 15.3 m/s horizontal component due east.
How far east of the great bombard will the projectile land, assuming the battlefield is flat? Give answer in meters.
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The acceleration of gravity is 9 . 8 m / s 2 vertically downward.
So the great bombard's projectile will take (49.0/9.8) = 5 seconds to reach peak height and an additional 5 seconds to come back to earth. It is therefore in the air for 10 seconds. The horizontal component is constant, so at 15.3 m/s, multiplying by 10 yields 153 m horizontal travel.