"Here's to dear old Boston / the home of the bean and the cod / where Lowells speak only to Cabots / and Cabots speak only to God."
There are five Lowells and seven Cabots at a certain gathering. Each Lowell is speaking to exactly one Cabot, and every Lowell is speaking to a different Cabot.
In how many ways can this occur?
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The first Lowell can choose any of the seven Cabots to speak to. Then the second Lowell can choose any of the remaining six (etc.) So the answer is 7 * 6 * 5 * 4 * 3 = 2520.