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Trampolining is an Olympic sport that involves gymnastics tricks performed sometimes 4-5 meters above the ground using a trampoline. You can see a video of this here . A female gymnast of mass 50 kg 50~\mbox{kg} lands on a trampoline, stretching it downward. If after she bounces she reaches a height of 5 m 5~\mbox{m} above the surface of the trampoline when it was fully stretched then how much energy in joules did the trampoline store?

Details and assumptions

  • You may assume the gymnast goes straight up and down, is a point mass, and adds no extra energy this bounce by jumping.
  • Take g g to be 9.8 m/s 2 9.8~\mbox{m/s}^2 .


The answer is 2450.

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13 solutions

Energy is the capacity to do work thus

W= fd (force x displacement )

Force= mg (mass x acceleration due to gravity)

F= 50 kg x 9.8 m/s^2

F= 490 N

W= 490N x 5m

W= 2450 J

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Fapeng Guerrero - 7 years, 6 months ago

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!!!!!!!!!!

Sherif Elmaghraby - 7 years, 5 months ago
Pushkar Sharma
Dec 2, 2013

Since energy is coserved, potential energy at max height is the total energy as kinetic energy at max height is 0. And, potential energy at max height = energy stored at max stretching of trampoline = mgh = 50kg x 9.8 ms^-2 x 5m = 2450 J

sir u have used nice reasoning !!

Devesh Rai - 7 years, 6 months ago

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Thank you!

Pushkar Sharma - 7 years, 6 months ago
Victor Song
Dec 2, 2013

Remember when the trampoline is fully stretched, its velocity will be zero therefore the equation to find the energy will be the potential energy:

Potential energy = mass * gravitation field strength * height

If we sub in the values we get: 5 * 50 * 9.8 = 2450 Joules

Sadman Sakib
Dec 14, 2013

Well its quite easy . we know that , W = Fx = mgh , where m is the gymnast's mass , g is gravity and h is what height she got up in the air .

Pham Tung
Dec 8, 2013

It is same the last issue . W = m . g .h = 50 . 9,8 . 5 = 2450 ( J )

Prasun Biswas
Dec 7, 2013

Stretched height of trampoline = 5 m

Mass of the body = 50 kg

So, Energy stored in trampoline = P.E of trampoline = mgh = 50 * 9.8 * 5 = 2450 J

Caio Serra
Dec 6, 2013

W= f x d W=(50x9,8)x5 W=(490)x5 W=2450 J

mgh =(50kg) (9.8m/s^2) (5m)

Rittik Das
Dec 5, 2013

Force=Mass Acceleration,Mass is 50kg and acceleration = 9.8m/sec^2....Therefore, Force=50 9.8kg m/sec^2....Displacement = 5m...Therefore work done=2450Joules, that can be written as 2.45E3

Honaraj Rn
Dec 4, 2013

e=mgh....here m=50kg,g=9.8,h=5m....energy=2450

Mohamed A.B
Dec 3, 2013

moving freely under gravity she has her weight acting downwards 50 × 9.8 50 \times 9.8 =490

you should recognize that the work done against her weight is actually the energy used which also equals the potential energy from stretching of the trampoline

work done against her weight= 50 × 9.8 × 5 50 \times 9.8 \times 5 =2450 joules

Vinay Saketh
Dec 2, 2013

work done=mgh; thus on substituting we get2450

As the weight can be calculated as (mass Cg). To know how much energy is stored we have a formula Energy Stored = Weight * Distance travelled Therefore weight w=50 9.8 = 490 N Energy stored = w d = 490 5 = 2450 Nm or Joules.

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