Box in a box

Geometry Level 1

The red square $ABCD$ has area = 16. The triangle $AEH$ has area = $\frac{3}{2}$ . Find the area of blue square.

NOTE: Figure is NOT drawn to scale

1 solution

Muneeb Aadil
Sep 28, 2017

Since $ABCD$ and $EFGH$ both are squares, all four triangles ( $AEH$ , $EBF$ , $FCG$ , $GDH$ ) will have the same area.

Thus, $EFGH$ = $ABCD -$ $4\times AEH$ $= 16 - 4\times(\frac{3}{2}$ ) $= 10$