In the figure shown there is a yellow rectangle that is surrounded by squares of different sizes.
If the smaller side of the yellow rectangle measures 40 cm, what is the length of its larger side?
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Let the side length of the green squares be x and the side length of the blue squares be y .
We can get the width from left to right of the entire figure in 2 ways, and can derive 2 expressions which therefore must be equal.
9 y = 6 y + 2 x
or,
6 y = 4 x .
We can see that the shorter side of the yellow rectangle is equal to 4 x − y
Therefore, 4 x − y = 4 0
Substituting in, 6 y − y = 4 0
or, 5 y = 4 0
hence, y = 8
As the length of the yellow rectangle is 6 y = 4 8 , this is the answer.