A cuboid contains a sphere of radius 2 and four unit spheres. The spheres are tangent to each other and to the box.
The height of the box can be expressed as , where A and B are coprime positive integers. Find .
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Consider a right triangle with the right angled corner at the center between the four unit spheres, the shorter side terminating at the center of one of the unit spheres, and the longer side terminating at the center of the sphere of radius 2. Let h be the height of the box. Then
a = 2
b = h − 1 − 2
c = 1 + 2
and we solve for h in this Pythagorean equation
a 2 + b 2 = c 2
which fairly quickly gets us h = 3 + 7 , and so the answer is 1 0
This is the quadruple Mickey Mouse, isn't it?