Boyle's law

Classical Mechanics Level 1

If an ideal gas is allowed to slowly expand to 4 times its initial volume, what is the ratio of the final pressure to the initial pressure?

4 1 2 1 4 \frac14 1 2 \frac12

July Thomas by July Thomas , 30, USA

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1 solution

July Thomas
Apr 30, 2016

Relevant wiki: Pressure

By Boyle's law,

P 1 V 1 = P 2 V 2 . P_1V_1 = P_2V_2.

Since V 2 = 4 V 1 , V_2 = 4V_1,

P 1 V 1 = P 2 ( 4 V 1 ) P_1V_1 = P_2(4V_1)

P 2 / P 1 = 1 / 4. P_2/P_1 = 1/4.

3 Helpful 1 Interesting 1 Brilliant 1 Confused

Yup. The same way. Just apply the mathematical expression.

Abhiram Rao - 5 years, 1 month ago

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