(x+5)/(x-6) = (x-1)/(x+2) , then find the value of x?
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This should've been written as (x+5)/(x-6) = (x-1)/(x+2)
Dude, this problem has two solutions. 2/7 and -2/7.
x − 6 x + 5 = x + 2 x − 1
(x+5)(x+2)=(x-6)(x-1)
x 2 + 7 x + 1 0 = x 2 − 7 x + 6
1 4 x + 4 = 0 or − 1 4 x − 4 = 0
x = 7 2 or x = − 7 2
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(x+5)/(x-6)=(x-1)(x+2)
(x+5)(x+2)=(x-6)(x-1)
x^2+7x+10=x^2-7x+6
take out x^2, move either the positive 7x and 6 or negative 7x and 10
choice 1: 10-6=-7x-7x
4=-14x
x=-2/7
choice 2:
7x+7x=6-10
14x=-4
x=-2/7
there is only one solution to this because x^2 has been taken out, therefore x=2/7 is an erroneous solution
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I finally found my mistake. :P
1 4 x + 4 = 0
1 4 x = − 4
x = 1 4 − 4
x = − 1 4 4
Oh dear. Sorry for the trouble.
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using componendo/ dividendo:
(x+5)/(x-6) = (x-1)/(x+2) or (x+5-x+6)/(x-6) = (x-1-x-2)/(x+2) or (11)/(x-6) = (-3)/(x+2) or 11x+4= -3x or 14x=4 or x=-2/7
hence, x=(-2/7)