BRAIN WORKS ~1

Algebra Level 4

IF x , y , z x, y, z ARE REAL NUMBERS SUCH THAT x + y + z = 5 x+y+z=5 AND x y + y z + z x = 3 xy+yz+zx=3 WHAT IS THE LARGEST VALUE THAT x x CAN HAVE?

5/3 NONE OF THESE 13/3 √(19)

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1 solution

James Wilson
Oct 1, 2017

My solution uses calculus. I'm interested to see what other solutions people come up with--as I am the first to post a solution. I started by solving for z z in the first equation (i.e. z = 5 x y z=5-x-y ), and substituting it into the second equation. After simplification, I get 5 y y 2 + 5 x x 2 x y = 3 5y-y^2+5x-x^2-xy=3 . Then, differentiating with respect to y y ... 5 2 y + 5 d x d y 2 x d x d y d x d y y x = 0 5-2y+5\frac{dx}{dy}-2x\frac{dx}{dy}-\frac{dx}{dy}y-x=0 . Setting d x d y = 0 \frac{dx}{dy}=0 , I get y = 5 x 2 y=\frac{5-x}{2} . Substituting that into 5 y y 2 + 5 x x 2 x y = 3 5y-y^2+5x-x^2-xy=3 , and solving for x x , I get x = 1 , 13 / 3 x=-1,13/3 .

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