What is the value of 1/2 of 2/3 of 3/4 of 4/5 of 5/6 of 6/7 of 7/8 of 8/9 of 9/10 of 1000?
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Denominatora and numerators cancek out leaving behind 1 0 1 0 0 0 = 1 0 0 .
(9!/10!) 1000= (1/10) 1000= 100
Converting the question into a multiplication problem:
2 1 × 3 2 × 4 3 × 5 4 × 6 5 × 7 6 × 8 7 × 9 8 × 1 0 9 × 1 0 0 0
Notice that the numbers 2 through 9 are repeated in the numerators and denominators. This means that they can be crossed out, so that leaves:
1 0 1 × 1 0 0 0 ,
which equals 1 0 0 .
It is asked to find
1/2 X 2/3 X 3/4 X 4/5 X 5/6 X 6/7 X 7/8 X 8/9 X 9/10 X 1000
Then all numbers will be canceled and the result would be.
1000/10=100
2 1 3 2 4 3 5 4 6 5 7 6 8 7 9 8 1 0 9 × 1 0 0 0 = 1 0 0
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2 1 × 3 2 × 4 3 × 5 4 × 6 5 × 7 6 × 8 7 × 9 8 × 1 0 9 × 1 0 0 0
1 0 1 × 1 0 0 0 = 1 0 0