Breaking a Stick

I have a stick of a certain length. I use my hands to break the stick into 2.

The probability that at least 1 of the 2 smaller sticks is at least half the length of the original stick is:

0% 25% 50% 100% 75%

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Jordan Cahn
Dec 13, 2018

Let the length of the original stick be L L , with shorter sticks of length l 1 l_1 and l 2 l_2 . If l 1 < 1 2 L l_1<\frac{1}{2}L and l 2 < 1 2 L l_2<\frac{1}{2}L then l 1 + l 2 < 1 2 L + 1 2 L = L l_1+l_2 < \frac{1}{2}L + \frac{1}{2}L = L But l 1 + l 2 = L l_1+l_2 = L , a contradiction. Therefore either l 1 1 2 L l_1\geq \frac{1}{2}L or l 2 1 2 L l_2\geq \frac{1}{2}L and the desired probability is 100 % \boxed{100\%} .

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...