Breaking limits

Calculus Level 2

True or False?

lim ⁡ x → 0 x 2 x = lim ⁡ x → 0 x 2 lim ⁡ x → 0 x \lim_{x\to0 } \dfrac{ x^2}x = \dfrac{ \displaystyle \lim_{x\to0} x^2 }{ \displaystyle \lim_{x\to0} x }

True False

Pi Han Goh by Pi Han Goh , 30, Malaysia

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Prokash Shakkhar
Dec 16, 2016

First we need to go back to definition.. lim ⁡ x → a f ( x ) g ( x ) = lim ⁡ x → a f ( x ) lim ⁡ x → a g ( x ) = l m , \lim_{x\to a}\frac{f(x)}{g(x)} = \frac{\lim_{x\to a} f(x)}{\lim_{x\to a} g(x)} =\frac{l}{m}, ;where m ≠ 0 m≠0 But according to the question above lim ⁡ x → 0 x = 0 \lim_{x\to 0} x =0 , which is an undefined form.. So, This limit can't be separated into a b \frac{a}{b} form..

4 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...