Breaking String (Part 2)

A bob of mass M = 0.5 k g M=0.5~kg is attached to the end of a string of length L = 5.6 m L=5.6~m . The other end of the string is attached to an anchor point.

The string and bob are initially horizontal, and the bob is given a downward vertical velocity v = 1 m / s v=1~m/s at time t = 0 t=0 . The string can withstand a maximum tension T = 12 N T=12~N without breaking.

Find the time when the string breaks.

Details and Assumptions

g = 10 m / s 2 g=10~m/s^2 in the downward vertical direction
• The string is taut at all times, from t = 0 t=0 to the time of breaking

Inspiration


The answer is 0.93298.

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1 solution

Nj Star
Mar 7, 2020

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