brilliant geometry puzzle
In the rectangle shown above, the areaa of the yellow and blue regions are given as 9 and 4 respectively. Find the area of red region.
You can use Swaroop's theorem to solve 》 bit.ly/Swaroop-theorem
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We note that the blue and yellow triangles are similar. Therefore that areas of the two triangles are proportional to the square of their linear dimensions. That is if the blue triangle has a base of 2 a and height of 2 h , the yellow triangle will have a base of 3 a and height of 3 h . Since 2 4 a h = 4 and 2 9 a h = 9 , a h = 2 .
Let the area of the red region be A . Then A + 9 = 2 1 ( 3 a ) ( 5 h ) = 2 1 5 a h = 1 5 ⟹ A = 1 5 − 9 = 6 .