A device named is launched which records the number of problems posted on Brilliant every second.IMAGINE that these problems were stored in a disc which had a limited capacity.
This was the data recorded by the brilliantometer -
In second - Total problem posted.
Till second ends- Total problems posted.
Till second ends- Total problems posted.
Till second ends- Total problems posted.
Till second ends- Total problems posted , and so on .........
If in 1 hour the disc was full and no more problems can be posted now , when was the disc half full? Express your answers in seconds.
I am extremely sorry for the inconvenience I caused to the people who solved this last time. I am re-posting this again.I am extremely sorry.
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1 hour = 3 6 0 0 seconds
So , when 3 6 0 0 seconds pass , the disc is full. So the disc was half full 1 second before it became full. So the disc was full as the 3 5 9 9 seconds pass.
I am extremely sorry for the inconvenience.