Sliding Numbers

A positive integer n n is a sliding number if the positive integers, x x , y y and k k , can be written as x + y = n \large x + y = n and 1 x + 1 y = n 1 0 k \large \frac{1}{x}+\frac{1}{y}=\frac{n}{10^{k}}

Note: The number n 1 0 k \frac{n}{10^{k}} is n n "shifted" by some k 0 k \geq 0 decimal places.

For example, 25 is a sliding number since 20 + 5 = 25 and 1/20 + 1/5 = 25/100.

What is the first sliding positive integer with 5 trailing zeros ?


The answer is 200000.

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1 solution

Brack Harmon
Jun 6, 2018

The number 2 is the first sliding sliding number, since 1 + 1 = 2 and 1/1+1/1 = 2 (2 isn't shifted any digits). No matter how many zeros you add, 2000... will always be a sliding number since it can be shifted with n 1 0 k \frac{n}{10^{k}} to accomidate 1/1000... * 2. 200 is the first sliding number with a run of 2 trailing zeros, 2000 with three and 200000 with 5.

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