During the hurricane a 16-meter-tall tree got fractured and its higher part fell down so that its tip touched the ground at the distance of 8 meters from the trunk. At what height is the fracture?
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I would urge caution when combining a ruler-and-compass construction with a distance estimation.
The task comes from a text book for mathematics in fifth grade (I only changed the numbers to get an integer as a solution). It appears that the pupils learn ruler-and-compass construction first, before they get to know Pythagorean theorem. This is actually the reason why I have made the construction to find a solution. I think it is an interesting approach too, so I wanted to show it.
Say the fracture is at a height h from the ground. The length of the broken top part of the tree is 1 6 − h . By Pythagoras, h 2 + 8 2 = ( 1 6 − h ) 2
Expanding, h 2 + 6 4 = 2 5 6 − 3 2 h + h 2
Cancelling and rearranging, 3 2 h = 1 9 2
Solving, h = 6
Did it the same way.
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I solved the task using ruler-and-compass construction. I am going to show the steps below: 1. This is the initial problem: 2. Draw circles of the same radius and the centers of points A and C, so that the circles intersect: 3. Connect the points D and E. The segment DE is a bisector of the line segment AC 4. The searched height is the segment BF, wchich is 6 units long: It is so because the segments AF and CF have equal length, which sum up to the initial height of the tree.