Browsers in math! Weird

Let $G=google; M=mozilla; Q=opera~mini$ , then

$3G=24$ or $\boxed{G=8}$

$2M+G=20$ $\implies$ $2M+8=20$ $\implies$ $\boxed{M=6}$

$M(Q)-Q=10$ $\implies$ $6Q-Q=10$ $\implies$ $Q=2$

Finally,

$G+ \dfrac{M}{Q}=8+\dfrac{6}{2}=8+3=$ $\color{#D61F06}\large{\boxed{11}}$

• Chrome = 8

• Firefox = 6

• Opera = 2

Now,

$\Rightarrow 8 + 8 + 8 = 24$

$\Rightarrow 6 + 6 + 8 = 20$

$\Rightarrow (6 \times 2) - 2 = 10$

$\Rightarrow 8 + (6 \div 2) = \color{#3D99F6}\boxed{11}$

Let $G=google$ , $M=mozilla$ , $Q=opera$ . Then:

$3G=24$ which means $G=24 \div 3=8$ .

$2M+G=20$ or $2M+8=20$ . Then $2M=20-8=12$ and so $M=12 \div 2 =6$ .

$M\times Q-Q=10$ or $(M-1) \times Q=10$ . Then $(6-1)\times Q=10$ which means $5\times Q=10$ . Therefore $Q=10 \div 5=2$ .

Finally $G+M \div Q=8+6\div 2=8+3=\boxed{11}$ as required.