Bug Zappers

Algebra Level 2

Bug Zapper #1 zapped a fair number of bugs, but Zapper #2, a louder one, zapped 22 more bugs than Zapper #1. However, it was Zapper #3, (Known as "Purple Lightning"), that set all records. It actually zapped 45 more bugs than #2 did. If all 3 zappers zapped a total of 398 bugs in total, how many were zapped Zapper #1 Alone?


The answer is 103.

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1 solution

David Warrak
Aug 7, 2018

We're trying to find the number of bugs #1 zapped so that's x. Then put all the numbers in, (I'm not going thru that) But this is what you come out with:

x=#1's zaps

x+22=#2's zaps

x+22+45=#3's zaps

398=total zaps

So put them all horizontal like this:

x+(x+22)+(x+22+45)+398

Then we put all the variables together and all the other numbers together, like this:

3x+89=398

Then subtract 89 from both sides.

3x+89-89=398-89

On the left we have just 3x left, and on the right, 398-89=309.

So now we have 3x=309

Now, divide both sides by 3.

3 x 3 \frac{3x}{3} = 309 3 \frac{309}{3}

On the left we have just x, and on the right we have 103, Which is the answer to this problem.

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