A body A is dropped froma a height
above the ground. At the same time another body B at a distance
from the projection of A from the ground is fired at an angle
to the horizontal. If the two collide at the maximum point of the trajectory of B the angle of the projection is given by
(A)
(B)
(C)
(D)
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x -axis movement
V 0 cos α t = d
y -axis movement
h − x is the height at the maximum point of the projection
From body A until h − x height
h − x = h − 4 . 9 t 2
− x = − 4 . 9 t 2
From body B until h − x height
h − x = V 0 sin α t − 4 . 9 t 2
Then
h − x = V 0 sin α t − x
h = V 0 sin α t
Finally
V 0 cos α t V 0 sin α t = d h ⇒ tan α = d h ∴ α = tan − 1 ( d h )