Bursting Gas
A glass bulb contains air at one atmosphere and 27 degrees Celsius. The maximum pressure the bulb can withstand is 2 atmosphere . The temperature at which it bursts is . Find .
The answer is 50.
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1 solution
According to Gay-lussac's Law , P1/T1 = P2/T2 . So , P1 ( Initial Pressure) = 1 atm and P2 (Final Pressure) = 2 atm. So , T1 = (27 + 273)K = 300 K . Now , solving for T2 , the temperature at which the gas bursts , we get T2 = 600 K = 6 * 100 K . Therefore , x = 6.