8-year-old Samantha visited Santa at a local department store. He gave her this riddle:
I started working at 15.
I spent 1/4 of my working life in a factory.
I spent 1/5 of my working life in an office,
and I spent 1/3 of my working life as a school caretaker.
For the last 13 years of my working life I've been Santa Claus.
How old am I?
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let the age of santa=x; then his working age=(x-15); so, (x-15)=((x-15)/3+ (x-15)/4+(x-15)/5)+13; from this we get x=75; therefore age of the santa is75
actually i just add up the fractions and it's 47/60. since his last working years were 13 , the denominator for 47 is 60 and 60-47 is 13. 47 years were the part of his life he worked other jobs. 47 is a fraction of 60 which is a whole. And that would mean that that whole is 60. 47 years plus 13 years we got 60 years. 60 years plus 15 years equals to 75 years
I used the same solution too. Yeay! :D
Let "x" be the number of working-life years. factory time: (1/4)x office time : (1/5)x school time : (1/3)x Santa time : 13 years
Working-life equation: (1/4)x + (1/5)x + (1/3)x + 13 = x 15x + 12x + 20x + 60 13 = 60x 47x + 60 13 = 60x 13x = 60*13 x = 60 (years he worked) Age = 15 + 60 = 75 yrs. old
i used the same method :D
i thnk the same :D
nice and neat solution :)
What is the biggest prime number ?
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its impossible to find the biggest prime no....i think
Since there is an infinite number of numbers, then there is an infinite number of prime numbers an no biggest one.
ok
well solved
same solution age = 75 :)
i got the logic but made a silly mistake... Good question...
i solve in little different way like,(x/3+x/4+x/5)=x-13
it is same
after finding 'x' +15
i got thhe logi but made a minure mistake
well, he is old enough to tell 8-years old girl this riddle :P
i don't understand this type of questions
that's not coming exact 60, x=x/3+x/4+x/5+13=> x=0.78x+13=> x=13/0.22=59.09 check it please
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1/3 + 1/4 + 1/5 = 47/60...not .78 This is a small difference, but it is the source of your error.
keep it in fraction..
y?
no error...
Hm? So did you do this? 5•4=20, 20•3=60, 60+15?
nice question
nice amulya
Call x = Santa's working years, we have:
4 1 x + 5 1 x + 3 1 x + 1 3 = x 6 0 4 7 x + 1 3 = x 1 3 = 6 0 1 3 x x = 6 0
so, Santa's age equal to: 15 + x <=> 15 + 60 = 75
can you clear the step of 47 how you got it ? can you explain more in detail ?
can u explain how 47 becomes 13.
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Take the x terms together, then it would be (60-47)/60
let the age of santa = y
let the working life of santa = x
So
y=x+15 .............(1)
x=(x/3)+(x/4)+(x/5)+13.................(2)
solve equation no. 2
x=60
subsitute this value of x in equation no.1
y=(60)+15
y=75
therefor age of santa = 75
yup.. of course...
yaa....
1/4+1/5+1/3=47/60 remaining = 13/60, so working life = 60, so total age=60+15=75
The total time spent by Santa in working = x.
Therefore, x = x/3 + x/4 + x/5 + 13.
Therefore, x=60.
Thus, Santa's total age = 60+15 =75.
Ans: 75 years.
(1/4 + 1/5 +1/3)*60 + 15+28=75
Let x be the working life of Santa in years. Then he spent,
4 x of his working life in the factory, 5 x of his working life in the office & 3 x of his working life as a caretaker. And for the last 1 3 years of his working life, he had been Santa. So we get the following equation :
4 x + 5 x + 3 x = x − 1 3
Solving this, we get x = 6 0 .
But he started working at the age of 1 5 years.
⇒ His age is 1 5 + his working life.
⇒ 1 5 + 6 0 = 7 5 .
Add up the fractional work experience and subtract from one to determine the fractional work experience as a Santa
i.e. 1 − 4 1 + 5 1 + 5 1 1 3
⇒ 6 0 1 3 1 3 = 6 0
So his age is 60 + 15 = 75
x=(x/3+x/4+x/5), we get x is 60 and 60+15=75
say,his total working life is x years.so (x\4)+(x\5)+(x\3)+13=X.then X=60.so he is 60+15=75 years old.
say,his total working life is x years.so (x\4)+(x\5)+(x\3)+13=X.then X=60.so he is 60+15=75 years old.
x = x/4 + x/5 + x/3 + 13, so x = 60.. then 60 + 15 = 75!!!
take the L.C.M of 4,5,3 and add 15 to it answer will be 60+15=75
Let x be the total working age. Then: 1/5x + 1/4x + 1/3x + 13 = x => x =60 He worked since he was 15 So total age =(60+15) = 75 years.
Age = 15 + (x/4 + x/5 + x/3 + 13)
or
Age = 15 + x
where x = Working Life
x = x/4 + x/5 + x/3 + 13
x = 9x/20 + x/3 +13
x = 47x/60 + 13
x - 47x/60 = (47x/60 - 47x/60) + 13
13x/60 = 0 + 13
13x/60 = 13
(13x/60) * 60 = 13 * 60
13x = 13 * 60
13x/13 = (13 * 60)/13
x = 1 * 60
x = 60
Age = 15 + 60
Age = 75
in the question the santa's age is show as 1.So we get the 1 as santa age. his work started age 15. the age from he did't work 13. 1=(1÷3,1÷4,1÷5)+13 from this we get 1=60 we get all ages except 15 so we add the work start age 60+15=75 So 1=75.So santa's age is 75 :)
let the working age of santa be X. Then his present age would be X+15. So, let's calculate his working age, i.e, X/4 + X/5 + X/3 + 13 = X => X=60. So, his present age = X+15=60+15=75.
let the age of the santa clause be x now, (x-15)=(x-15)/4+(x-15)/5+(x-15)/3 +13 implies that,x=75 years
let age of santa is=x,then x=x/4+x/5+x/3,we get x=60.hence his age will be=working age+15,which is =75.
here , let x/4 life in factory , x/5 in other and x/3 in any other so adding this we get 47x/60 so 47 years in all these works and 13 years as santa and 15 years as child so 15+13+47=75 years..that's it
Let x be the working life so (1/4)x + (1/5)x + (1/3)x + 13 = x. Solve and eventually you will get 13x = 780. Solving this you will get x = 60. Then add 15 and you will get age as 75.
get the L.C.M of the 3 values 4,5,3 which are the denominators of the fractions the answer will be 60 hence we get the fractions 15/60, 20/60 , 12/60 add these fractions : 47 / 60 subtract from 1 the above fraction now we form an algebric equation: 13/ 60 * (X-15) = 13
1/4 + 1/5 + 1/5 = 47/60 , Since the last 13 years of his life represent 13/60, Therefore, his working life= 47 + 13= 60. Therefore, his age= 15 + 60=75 years #
consider total working life as x..........find solution and add 15 to know his age
(1-(1/4+1/5+1/3))*X = 13
X=13/(1-(47/60))
X= 13/(13/60)
X=60
work life = 60
Age = work life + age during start of work Age= 60+15 Age =75
Let Santa's work Life be x. Then x=(1/3+1/4+1/5). The answer in decimal form is 0.78. so he spent 78% of his life as working in Factory,Office and as School caretaker. Now the remaining working life is 22%. We know that he spent 13 years of his remaining working life as SANTA. so 22% of x is equal to 13. Thus we get x=60. Now since he started working at 15. His age would be x+15 that is 60+15= 75. This is how i got to the answer.(There is a small error in the question that x =59.09. If we round off it it becomes 59. thus 59+15=74. So the correct answer should have been 74)
1/4 + 1/5 + 1/3 = 13/60 remaining years = 1/1 – 13/60 = 13/60 so 13/60 part = 13 years then 1 part = 60/13 × 13 = 60
Let total age of Santa be x, 15 years no work. So Working Life = x-15.
Equation is - 15 + 13 + (x-15)/4 + (x-15)/5 + (x-15)/3 = x
let the age of santa=x; then his working age=(x-15); so, (x-15)=((x-15)/3+ (x-15)/4+(x-15)/5)+13; from this we get x=75; therefore age of the santa is75
Let the total working life is 'x' As per x-(x/3+x/4+x/5)=13 we can find x=60 Total life will be, 15+60 = 75
1/3 +1/4 +1/5 =47/60
So, he has spent 13 years of his working life to be Santa Claus
60/60 - 47/60 = 13/60
1 year=1/60
60years=60/60 60years+15years=75 years
Are you assuming that he must have working for 60 years?
where did you get 47?
Let X be his working life...
First, you have to find the value of X and it will be possible if you deduct the WHOLE WORKING life with the given Fraction giving a remaining working life which is 13
Illustration:
X - (47/60)(X) = 13 (13/60)(X) = 13 X = 60
Then, to get his present age, add his working life with his age when he started working
15 + 60 = 75 ;)
Started working at 15 yrs of age, suppose age is X yrs add X-15/4 + x-15/5 + X-15/3 + 15 +13 will be equal to X simplifying above we get 75 yrs Ans
K.K.GARG,India
Assume that his working life is x years.
Now from the question we can derive the equation that,
x 4 1 + x 5 1 + x 3 1 + 1 3 = x
from this equation we find the value of x is 6 0
He started the job at the age of 1 5 , so he is 7 5 .
let the working life of Santa is x. so the equations becomes x= x/3+x/4+x/5 comes out to be 60. than simply add 15 to it.
Why didn't we add 15 rhough..?
i agree
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let the working life of santa be 'x' years...x=(x/3+x/4+x/5)+13. from this equation, we get x=60. as santa started working at 15, his age will be 15+60=75.