Evaluate the expression 2 0 1 6 3 + 1 2 0 1 6 4 + 2 0 1 6 2 + 1 .
If the answer can be expressed as a mixed fraction in simplest form a c b , find a + b + c .
Note:
Solve this problem without using a calculator.
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Correct! That's how I did it. Just being picky, you could show how you manipulated the numerator in order to get a difference of two squares by adding and subtracting x 2 .
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I do not want the solution to be lengthy than necessary so I decided not to wrote that part, but for the sake of completeness, I edit the solution. Please see whether it suits you.
I am in class 8th I can't understand properly.Can you try another method to explain.
This = ( x^4 + 2x^2 + 1 ) -x^2 / x^3 + 1 = ( x^2 + 1 )^2 - x^2 / x^3 + 1
Brilliant!!!
Brilliant!
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Let x = 2 0 1 6 . We can rewrote this expression into x 3 + 1 x 4 + x 2 + 1 . This equals to x 3 + 1 x 4 + x 2 + 1 = x 3 + 1 x 4 + x 2 + x 2 + 1 − x 2 = x 3 + 1 ( x 4 + 2 x 2 + 1 ) − x 2 = x 3 + 1 ( x 2 + 1 ) 2 − x 2 Which may be simplified to ( x + 1 ) ( x 2 − x + 1 ) ( x 2 + x + 1 ) ( x 2 − x + 1 ) = x + 1 x 2 + x + 1 = x + x + 1 1 Therefore a + b + c = x + 1 + ( x + 1 ) = 2 x + 2 = 2 ( 2 0 1 6 ) + 2 = 4 0 3 4