But there's two values of y y , no?

Calculus Level 4

If the positive value of d y d x \dfrac{dy}{dx} of the y = x y y = x^y at x = 2 x = \sqrt2 is equal to A 1 ln B \dfrac{\sqrt A}{1 - \ln B} , where A A and B B are positive integers , find A × B A\times B .


The answer is 16.

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