Which of the following logarithms is greater? lo g 9 7 1 or lo g 8 6 1
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Whenever I see the word "clearly" in a solution, I think the writer has not bothered to write up an explanation. The point of a solution is to work through the problem so that it makes sense to anyone! "Clearly", "evidently", "obviously" are not, in my opinion, words used in a good solution.
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Thanks for the scolding, Andrei. :) I do realize that the use of these words raise red flags for some, but in my opinion they can be used when writing for specific audiences, (although I do draw the line at the word "obviously"; that one is a definite non-starter in any situation). I felt that, for a level 3 problem solver, the fact that 6 4 6 1 > 8 1 7 1 would be quite evident upon observation, hence I felt I could use the word "clearly" without appearing intimidating or condescending. However, out of respect for you and your criticism, I have edited my solution to include a brief proof of my initial claim. I hope that you find it suitable.
In considering how to phrase a solution, there is a fine line between offering too much exposition and too little. For some readers "too much" can be tedious and unnecessary, and for others "too little" can be cryptic and unsatisfying. I prefer brevity so long as it does not compromise clarity, and in this case I felt that my initial claim was sufficiently self-evident to justify the use of the word "clearly" without further explanation. That being said, I did find it an interesting exercise to provide as straightforward a proof as possible. :)
6 1 is closer enough to 8 2 than 7 1 is to 9 2 , so l o g 8 6 1 is greater. That was my reasoning
While that's clever intuition that worked out here, it turns out that this is not always the case. For example, 55 is closer to 8 2 = 6 4 than 71 is to 9 2 = 8 1 , but lo g 8 ( 5 5 ) < lo g 9 ( 7 1 ) .
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Yes, we even have that lo g 8 ( 5 6 ) < lo g 9 ( 7 1 ) , which would be quite risky to intuit.
This intuition is dependent on the ratio of given values. I am not a real analysis student, not currently, maybe in future I will do. But my mathematical experience tells me that analysing such things requires the analysis of their ratios.
By change-of-base, we have
lo g 8 6 1 = lo g 8 lo g 6 1 = 3 lo g 2 lo g 6 1 = 3 1 lo g 2 6 1
and
lo g 9 7 1 = lo g 9 lo g 7 1 = 2 lo g 3 lo g 7 1 = 2 1 lo g 3 7 1 .
Note: Both lo g 2 6 1 and lo g 3 7 1 are positive.
Observe that,
lo g 2 6 1 < 6 ⟹ 3 1 lo g 2 6 1 < 2
and
lo g 3 7 1 < 4 ⟹ 2 1 lo g 3 7 1 < 2 .
Notice that it only takes one-third of lo g 2 6 1 to be less than 2, whereas it takes one-half of lo g 3 7 1 to be less than 2. Since both lo g 2 6 1 and lo g 3 7 1 are positive, it must follow that lo g 2 6 1 > lo g 3 7 1 .
Equivalently, lo g 8 6 1 > lo g 9 7 1 .
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Note first that 6 4 6 1 > 8 1 7 1 .
(Proof: We have that 6 4 0 3 0 < 2 4 3 3 0 ⟹ 6 4 3 < 8 1 1 0 ⟹ 1 − 6 4 3 > 1 − 8 1 1 0 ⟹ 6 4 6 1 > 8 1 7 1 . )
By the change of base rule we then have that
lo g 8 ( 6 4 6 1 ) > lo g 8 ( 8 1 7 1 ) = lo g 9 ( 8 ) lo g 9 ( 8 1 7 1 ) > lo g 9 ( 8 1 7 1 ) ,
since we also know that 0 < lo g 9 ( 8 ) < 1 . This implies that
( lo g 8 ( 6 1 ) − lo g 8 ( 6 4 ) ) > ( lo g 9 ( 7 1 ) − lo g 9 ( 8 1 ) ) ⟹ lo g 8 ( 6 1 ) > lo g 9 ( 7 1 ) ,
since lo g 8 ( 6 4 ) = lo g 9 ( 8 1 ) = 2 .