We have an atom having charge 5 e 5e distributed uniformly on its surface as shown on the figure.
We divided this atom into 2 equal parts, In what proportion will charge distribute on each part?

Details :

  • e = 1.6 × 1 0 19 C e = 1.6 \times 10^{-19} C
Original Problem
e / 4 e e / 4e 3 e / 2 e 3e / 2e 2.5 e / 2.5 e 2.5e / 2.5e 2 e / 2 e 2e / 2e 3 e / 3 e 3e / 3e None of these

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1 solution

You should know what's *Quantization of Charge first.

Simple, charge doesn't remain in fraction . Which means , 0.5e or 1.56e charge is invalid, while 1e,5e etc are valid. This is the quantization of charge.

So, when you divide the sphere, 2 electrons goes on a hemisphere with charge 2e , and 3 electrons goes on the other with 3e charge .

Hence, the ratio 3 e 2 e \frac{3e}{2e}

Can you explain why the magnitude of the charge will be 3e and 2e instead of 4e and e?

Mbah Abal - 5 years, 2 months ago

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Yeah. That's a really weird. I wonder I didn't notice it back than. You can submit a Report!

Muhammad Arifur Rahman - 5 years, 1 month ago

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