You just won enough money from a lottery to buy a house! Unfortunately, the money only comes in mickles and bimes...
Mickles are worth and bimes are worth .
The problem is that the house you are buying doesn't have a set price, and you must buy the house for the EXACT price.
The price of the house is anywhere between to . Is it true you can guarantee that you can choose a combination of mickles and bimes such that you can purchase the house?
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Consider the following combinations:
4 ∗ $ 0 . 0 3 = $ 0 . 1 2
$ 0 . 0 7 + 2 ∗ $ 0 . 0 3 = $ 0 . 1 3
2 ∗ $ 0 . 0 7 = $ 0 . 1 4
Since this is 3 consecutive amounts of cents in a row, we can simply add a multiple of $ 0 . 0 3 to each to achieve any cost greater than $ 0 . 1 2 . Since $ 0 . 1 2 ≤ $ 1 1 1 , 1 1 1 . 1 1 , You can definitely buy the house for the exact price!
i.e.
4 ∗ $ 0 . 0 3 + $ 0 . 0 3 = $ 0 . 1 5
$ 0 . 0 7 + 2 ∗ $ 0 . 0 3 + $ 0 . 0 3 = $ 0 . 1 6
2 ∗ $ 0 . 0 7 + $ 0 . 0 3 = $ 0 . 1 7