Four Mondays And Four Fridays

Logic Level 2

Ancient Ahmose was looking at the month of January on a calendar of some years past. He noticed that there were exactly 4 Mondays and 4 Fridays.

According to his calendar, what day of the week was January 1 st 1^\text{st} ?

Monday Tuesday Wednesday Thursday Friday Saturday Sunday

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2 solutions

There are 31 = 7 × 4 + 3 31 = 7\times 4 + 3 days in January. Therefore, only three days can occur 5 5 times.

Neither the 1 st 1^\text{st} , nor the 2 nd 2^\text{nd} , nor the 3 rd 3^\text{rd} can be a Monday or Friday, since this would imply that either the 2 9 th 29^\text{th} , 3 0 th 30^\text{th} or 3 1 st 31^\text{st} would be the fifth Friday or Monday.

The constraints of the problem are only true when the first, second and third , respectively, are Tuesday, Wednesday and Thursday . Thus, the first of January is a Tuesday.

Nice question!

Akhash Raja Raam - 5 years, 3 months ago

The picture is cofusing.😄

Rimy Babul - 5 years, 1 month ago

A very good question

Biswajit Barik - 4 years, 5 months ago
Achille 'Gilles'
Mar 11, 2016

In a 31 days month there are:

  • 3 consecutive weekdays that will appear 5 times (which are the 1st. 2nd and 3rd of the month).
  • 4 consecutive weekdays that will appear 4 times,

So in this problem, those three 5 appearances days are going to be Tuesday to Thursday therefore January 1st is going to be on Tuesday.

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